Abstract
There are n people, each of whom is either a knight or a spy. It is known that at least
k knights are present, where n/2 < k < n. Knights always tell the truth. We consider
both spies who always lie and spies who answer as they see fit. This paper determines the
minimum number of questions required to find a spy or prove that everyone in the room is
a knight. We also determine the minimum number of questions needed to find at least one
person’s identity, or a nominated person’s identity, or to find a spy (under the assumption
that a spy is present). For spies who always lie, we prove that these searching problems, and
the problem of finding a knight, can be solved by a simultaneous optimal strategy. We also
give some computational results on the problem of finding all identities when spies always
lie, which show that a plausible suggestion made by Aigner is false. We end by stating some
open problems. The questioning strategies in the paper have applications to fault finding
in distributed computing networks.
Original language | English |
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Pages (from-to) | 2754–2766 |
Number of pages | 13 |
Journal | Discrete Mathematics |
Volume | 339 |
Issue number | 11 |
Early online date | 11 Jun 2016 |
DOIs | |
Publication status | Published - 6 Nov 2016 |